Question

Hi all , I am trying to solve for x
sqaure root of 9x^2 - 16 = 3x - 4
can anyone show me the wroking out for this?
Much appreciated
A

Answer 1

\[\sqrt{9x^2 - 16} = 3x - 4\]
Is this what you mean?

Answer 2

yes thats it

Answer 3

Square both sides and rearrange, your x^2 terms will cancel.

Answer 4

ok thanks

Answer 5

Did you get it?

Answer 6

9x^2 - 16 = (3x - 4)^2
9x^2 - 4^2 = 9x^2 + 4^2 - 2* 3* 4*x
2*4^2 = 2 * 3 * 4 * x
4 = 3 * x
x = 4/3