plz solve this question and answer it soon i need the answer quickly plz : the question is : if tan35=2a-1 then solve (sin145-sin235)/cos325
2a=tan35+1 a=1/2*(tan35+1)
0.85010376910485488972926135972242
dear duke we dont neet to find a we need to solve (sin145-sin235)/cos325
there is nothing to solve there we solve equations that is an expression do you mean approximate or simplify?
translation maybe but one statement stand on it's on as myininaya states
approximate
1.700207538
1.7002075382097097794585227194448 same as myininaya
myninaya can u write the way u solved plz?
but with a closer approximation lol
i mean u do duke have the closer one
ok roh do you have a calculator
oh what type of calculator? hp or ti order of operations is the problem most likely
go to mode put in degrees
lolz any way without calculator through any trignmoetry formula
((sin(145))-(sin(235)))/(cos(325)) in ti32
i did like this : (sin(90+55)-sin(90+55))/cos(270+55)
sin(145)-sin(235) =sin(145)-sin(145+90) =sin(145)-[sin(145)cos(90)+sin(90)cos(145)] =sin(145)-[sin(145)*0+1*cos(145)] =sin(145)-cos(145) --------------------- cos(325)=cos(180+145)=cos(145)cos(180)-sin(145)sin(180) =cos(145)*(-1)-sin(145)*0 =-cos(145) so we have \[\frac{\sin(145)-\cos(145)}{-\cos(145)}=\frac{\sin(145)}{-\cos(145)}+1=-\tan(145)+1\] hmm... thinking....
i dont see how to not do it with a calculator anyone else?
without*
sin (145) = sin (180- 35) = sin 35 cos(325) = cos(360 - 35) = cos35 if only there was some way to convert the sin(235) to either cos or sin of 35
sin (270-35) = sin 235 thanks joe
sin(235)=sin(270-35) lol
i was gonna say that duke
LOL im tired as hell, thats it.
lol duke is awesome :)
i agree the answer is simple now lol
so the answer is: \[\frac{\sin(35)+\cos(35)}{\cos(35)} = \tan(35)+1 = 2a-1+1 = 2a\] ? im walking into the middle of this, trying to catch up.
yeah i got the answer thanks all joe is right so we will have the answer like this : sin 35+sin35/ cos 35 = tan(35)+1 so we have from the question that tan 35=2a-1 so we have: 2a-1+1= 2a
thank you joemath and myininaya
Dont forget duke!
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