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OpenStudy (anonymous):
integrate x^3/sqroot 16-x^2 dx
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OpenStudy (dumbcow):
u = 16- x^2 du = -2x dx \[=-\frac{1}{2}\int\limits_{}^{}\frac{16-u}{\sqrt{u}}du\]
OpenStudy (dumbcow):
can you do it from there
OpenStudy (anonymous):
i am confuse
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