Question

Find the area of parallelogram ABCD given mA = 30 and the following measures.



AD = 4square root 3 in.; AB = 8 in. Area = times the square root of sq. in.

Answer 1

what is mA?

Answer 2

m is the measure and it just representing 30 A = 30

Answer 3

AX / AD = sin30 = 1/2 => AD = 2 AX
area = AX * 8 = AD/2 * 8 = \[2\sqrt{2} * 8 = 16 \sqrt{2}\]

Answer 4

square inches :P

Answer 5

maybe sin30 = sqrt{3}/2

Answer 6

The length of the base of the triangle is b, the length of the corresponding altitude is h, and the area is A. Find the missing part.



b h A
___ in. 5 in. 10 sq. in.