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Mathematics 17 Online
OpenStudy (anonymous):

Determine the integral of tan inverse x dx

OpenStudy (anonymous):

You mean \[\int\arctan{x}dx?\]In that case,\begin{eqnarray*} \int\arctan{x}dx&=&\int (x')\arctan{x}dx \\&=&x \arctan{x} - \int\frac{x}{1+x^2} dx \\&=&x \arctan{x}-\frac{\log(1+x^2)}{2} + C.\end{eqnarray*}

OpenStudy (anonymous):

love that integration by parts!

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