Question

Solve this system of equations using substitution. Put your answer in ordered pair form, (x, y).
m + n = 1000
0.05m + 0.06n = 57

Answer 1

need help

Answer 2

m + n = 1000 (1)
0.05m + 0.06n = 57 (2)

frm (1) we get
m = 1000 -n
substitute this in (2)

0.05(1000 - n) + 0.06n = 57
50 - 0.05n + 0.06n = 57
0.01n = 57 - 50
n = 7/0.01
n = 700

Answer 3

now substitute n = 700 in (1)

m + 700 = 1000
m = 1000 - 700
m = 300

so solution set is (300, 700)

Answer 4

normally we use x and y as variables and while writing the solution we first write the value of x then y in the form (x,y)

in your case, the variables are m and n instead of x and y
so (x,y) is same as (m,n) = (300, 700)