Two cyclists, 30 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 1 hr later, at what average speed is each cyclist traveling?
slower cyclist _____ mi/hr
faster cyclist ______ mi/hr

Question

Two cyclists, 30 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 1 hr later, at what average speed is each cyclist traveling?
slower cyclist _____   	  mi/hr
faster cyclist    ______	  mi/hr

anonymous · Answer

10 mph and 20 mph

anonymous · Answer

that's right:

1hr=30mi/(2x+x)mi/h
x=10mi/h

answers:
10 and 20 mph