Question

6/y+2 +2/3y

Answer 1

20y +4 / 3y^ + 6 y

Answer 2

is this
\[\frac{6}{y+2}+\frac{2}{3y}\] and if so what are you supposed to do, add?

Answer 3

if so answer is
\[\frac{6\times 3y+2(y+2)}{3y(y+2)}=\frac{18y+2y+4}{3y(y+2)}=\frac{20y+4}{3y(y+2)}\]