Question

PLEASE HELP ME WITH LINEAR ALGEBRA!

Answer 1

Here's the problem..

Answer 2

Again I just want to know how to find:
[T]b and [T(v)]b

Answer 3

that looks surprisingly easy

Answer 4

please explain!!! PLEASE!!!

Answer 5

I mean I havent done this in about 3/4 of a year

Answer 6

JUST DO IT.... PLEASE U're gonna save my booty for the quiz haha..

Answer 7

I know its easy i just fell asleep halfway thru the lecture... =O

Answer 8

im not 100% sure but dnt you just multiply the components by the basis

T[b} = (x-y) times first vector + (y-x) times second vector + ( x-z) times third vector

Answer 9

think thats it , no gaurantee though

Answer 10

(2x -y -z , y-z , 0 )

Answer 11

let me check the answer..

Answer 12

thats the first one I think , as a row vector

Answer 13

my answer is completely different.. uploadin it..

Answer 14

by the way I already found [v]b i know how to get that i need everything else..

Answer 15

yeh so V[b] should be equal (2, 2, 4 ) I think

Answer 16

[v]b is actually (110)

Answer 17

yeh well then my answers are prob wrong lol

Answer 18

now i think its (3,2,4 ) lol

Answer 19

no (2,2,4 )

ahh im just going to stop

Answer 20

DAMN ISNT ANYONE GONNA HELP ME WITH THIS.....

Answer 21

Tb by columns (1, -1, 0), (3/2, 1/2, 1/2), (1/2, 1/2, 1/2) hopefully. (set an arbitrary vector with B).

I saw your message but by time I was finished with that maddening cos thing I was done in, sorry.

(Btw, I prefer applied linear algebra (or geometric algebra) not this sort of stuff, not my bag at all).