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evaluate the function at the given values of x, if possible f(x)= 2x-1/x^2 (a) x=2 (b) x=-1
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a) 3/4 b)-3 did u really not kno how to do that?
a f(x)= 2(2)-1/(2)^2=15/4 b f(x)= 2(-1)-1/(-1)^2=-3
\[f(x)=\frac{2x-1}{x^2}\] \[f(2)=\frac{2\times 2-1}{2^2}=\frac{4-1}{4}=\frac{3}{4}\]
\[f(-1)=\frac{2\times -1-1}{(-1)^2}=\frac{-2-1}{1}=-3\]
the way its written a) is 15/4 but i think he meant to write it the way satellite73 wrote it
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