Question

can someone please help me

Find the area of parallelogram ABCD given mA = 30 and the following measures.



AD =4 sqrt of 3 in.; AB = 8 in. Area = times the square root of sq. in.

Answer 1

turn them into multiple shapes and go from there.

Answer 2

cos60 = AX/AD

Answer 3

AX = AD cos(60) = 4sqrt(3) x 1/2 = 2sqrt(3)

Area = base times perpendicular height = 2sqrt(3) x 8 = 16sqrt(3) in^2

Answer 4

so its 8 and 16