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Mathematics 16 Online
OpenStudy (anonymous):

In a regular pentagon ABCDE and regular hexagon MNOPQR, 2AB = 3MN and CD + QR = 10. Which is 4BC + 5PQ? 44 42 38 33

OpenStudy (anonymous):

44

OpenStudy (anonymous):

AB=CD=BC, MN=QR=PQ

OpenStudy (anonymous):

thank you :)

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