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2x-x^2/4x^2+8x
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u want to simplify this
depending on how you wrote it... 2x-x^2/4x^2+8x = 10x - .25 or (2x-x^2)/(4x^2+8x) x=2
2x-x*2 x(2-x) 2-x ------- = ------- = ------ 4x*2+8x x(4x+2) 4x+2
what equal again with (2-x)/2(2x+1)
\[\frac{2x-x^2}{4x^2+8x}=\frac{x(2-x)}{4x(x+2)}=\frac{2-x}{x(x+2)}\]
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hey mr satelite you have missed one 4 in denominator or changed the 4 with x
yes ok the correct result is 2-x ------ 4(x+2)
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