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antiderivative. given the graph of f(x) passes thru the point (6,3) and the slope of its tangent line at (x,f(x)) is 2x+6. what is f(5)?
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hrmm, so we want to integrate 2x+6 right? x^2+6x+C and we know that 6 in that should give us 3 as y
6^2+6*6+C=3 solve for C
C=-69 so x^2+6x-69. plug in 5 for x and i get -19?
is that way off?
yea i plugged into the calculator and F(5) was -14
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oh yeah that's what i meant -14. made a arithmetic error when i checked it
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