Hi everyone, I'm new.

(3x^2)^2y^4
-----------
3y^2

I am supposed to simplify this fraction but am have trouble with my order of operations

Question

Hi everyone, I'm new.

(3x^2)^2y^4
-----------
3y^2

I am supposed to simplify this fraction but am have trouble with my order of operations

anonymous · Answer

is it:
$$(3x ^{2})^{2}*y ^{4}/(3*y ^{2})$$
?

anonymous · Answer

Oh yes, how did you write it so nicely?

anonymous · Answer

$$=3^{2}*x ^{2*2}*y ^{4}/(3*y ^{2})=(9x ^{4}*y ^{4-2})/3=$$
finish it please.
I used Equation button under the box (when you write your answer/question)

anonymous · Answer

Okay, thank you. :) Just had trouble with figuring out how to expand it like that.

anonymous · Answer

no problem - let me know if there are more questions.
what did you get as a final answer?

anonymous · Answer

$$3x ^{4}y ^{2}$$
That is what I got for my final answer.

anonymous · Answer

Good :))

amistre64 · Answer

welcome to earth :)