Question

If AC = 20 and BD = 50, find the perimeter of the rhombus.

Answer 1

107.7?

Answer 2

AM = 10
BM = 25
apply pythagorean theorem
10^2 + 25^2 = 725
square root it and you get 29. something
multiply it by 4 for all the sides of the rhombus since they are equal and you get 107.7 soemthing

Answer 3

do u think u can help me on my next 2 questions?

Answer 4

I can try :)

Answer 5

It will be equal to

\[P = 4 \sqrt{\left(\frac{AC}{2}\right)^{2} +\left(\frac{BD}{2}\right)^{2}}\]

and hence perimeter equals 107.7

Answer 6

i put it up there