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Rhombus CGRN is joined at rectangle BCND at segment CN. If BC - BD = 14 and DN + NR = 34, which is 4GR?
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BC - CD = 14 DN + NR = 34 as BC = DN (opp sides of rectangle) so eq 1 becomes DN - CD = 14 Now DN = 14 + CD and from eq 2 DN = 34 - NR 14 + CD = 34 - NR NR = CD = x (sides of a rhombus) 14 + x = 34 - x 2x = 20 x = 10 GR = x = 10 4GR = 4 x 10 = 40
thank you bt i have 1 more then im done
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