Question

Rhombus CGRN is joined at rectangle BCND at segment CN. If BC - BD = 14 and DN + NR = 34, which is 4GR?

Answer 1

BC - CD = 14
DN + NR = 34
as BC = DN (opp sides of rectangle)
so eq 1 becomes DN - CD = 14
Now DN = 14 + CD
and from eq 2 DN = 34 - NR
14 + CD = 34 - NR
NR = CD = x (sides of a rhombus)
14 + x = 34 - x
2x = 20
x = 10
GR = x = 10
4GR = 4 x 10 = 40

Answer 2

thank you bt i have 1 more then im done