Question

consider the following quadratic equation:
10x^2+19x+9=3
solve the quadratic equation above by factoring and enter solution

Answer 1

(2x+3)(5x+2) was correct answer from step 1

Answer 2

10x^2+19x+9-3=0
10x^2+19x+6=0
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lets think
we need to find factors of a*c that add up to be b
a*c=10*6=5*12=15*4
15+4=19
so we have
10x^2+15x+4x+6=0
5x(2x+3)+2(2x+3)=0
(5x+2)(2x+3)=0
so we have
x=-2/5 or x=-3/2