Question

consider the following quadratic equation:
x^2-16x+64=0
using the standard form ax^2+bx+c=0 of the quadratic equation above, factor the left hand side of the equation into two linear factors.

Answer 1

(x-8)^2 = 0

Answer 2

recognize a "perfect square" as
\[a^2+2ab+b^2=(a+b)^2\] in this example
\[a=x,b=-8\]