Question

use f(x)=3x-4 and g(x)=2x^2 to evaluate each of the following
(a)(f+g)(3) (b)(f-g)(-2) (c)(fg)(7) (d)(f/g)(0)

Answer 1

(a)(f+g)(3)=(3x-4)+(2x^2)
=(3(3)-4)+(2(3)^2)
=(9-4)+(2*9)
=5+18
= 23

Answer 2

thank u

Answer 3

(b)(f-g)(-2)=(3x-4)-(2x^2)
=(3(-2)-4)-(2(-2)^2)
=-10-8
=-18

Answer 4

thank you so much I am so lost in this that I did not know there were two answers.

Answer 5

(c)(fg)(7)=(3(7)-4)*(2(7)^2)
=(21-4)(2*49)
= 17*98
=1.666

Answer 6

(d)(f/g)(0)=\[\frac{3x-4}{2x^2}=\frac{3(0)-4}{2(0)^2}=\frac{0-4}{0}=0\]

Answer 7

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