Question

the denominator of a fraction is three more than twice the numerator. If both the numerator and denominator are decreased by three, the simplified result is 5
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13. Find the original fraction

Answer 1

Let x = the numerator
2x+3 = the denominator
according to the problem :
x-3 5
------- = ----
2x+3-3 13

cross multiply

13x-39= 10x
3x=39
x=13 numerator
2x+3=26+3=29 the denominator

Original fraction is: 13/29

Answer 2

Please review and ask any question for clarification. I gotta run but will return when I am notified.