Question

factor the polynomial using a special factorization:
40x^5+5y^3x^2

Answer 1

5*x^2*(2*x+y)*(4*x^2-2*x*y+y^2)

Answer 2

first factor out a
\[5x^2\] then you will have the sum of two cubes

Answer 3

like the last one but this time
\[a^3+b^3=(a+b)(a^2-ab+b^2)\]

Answer 4

\[5x^2(8x^3+y^3)\] and here
\[a=2x,b=y\]