Question

Find the equation of a circle in standard form where C(6, -2) and D(-4, 4) are endpoints of a diameter.

Answer 1

first find the center, which is the middle of the two points. it is
\[(\frac{6-4}{2},\frac{-2+4}{2})\] or
\[(-1,1)\]

Answer 2

dam i made a mistake. the center is not
\[(-1,1)\] it is
\[(1,1)\]

Answer 3

bad arithmetic. now you need the radius from the distance formula
\[r^2=(6-1)^2+(-2-1)^2=5^2+3^2=25-9=34\]

Answer 4

so your equation is
\[(x-1)^2+(y-1)^2=34\]