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appreciate the help! Solve using substitution 8x-7y=-5 x-8y=-2
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second equation solve for x via \[x=8y-2\]
8(8y-2)-7y ?
yes
don't forget the =-5, gets important
then replace in first equation being careful with parentheses \[8(8y-2)-7y=-5\] \[64y-16-7y=-5\] \[48y=-5+16\] \[48y=11\]
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oh mistake sorry
64-7=57
y=11/57 and subsitute in
\[8(8y-2)-7y=-5\] \[64y-16-7y=-5\] \[57y=-5+16\] \[57y=11\] \[y=\frac{11}{57}\]
looks like you got it!
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^what he said
x=-26?
x=(88/57)-(114/57) x=-26/57
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