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form a polynomial f(x) with real coefficient having the given degree and zeros: degree:5; zeros: 2, -3i and 4-i
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f(x)=(x-2)(x+3i)(x-(4-i))(x-3i)(x+(4-i))
f(x)=(x-2)(x+3i)(x-4+i)(x-3i)(x+4-i)
yep
the answer is f(x)=x^4+2ix^3-6ix^2-18i-6x^3+17x^2-49x+72 ... is it right??
^ why would the answer be degree 4?
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