Question

consider the following quadratic equation:
5x^2+16x+9=6
using the standard form ax^2+bx+c=0 of the quadratic equation above, factor the left hand side equation into two linear factors

Answer 1

\[5x^2+16x+3=0\] is a start

Answer 2

\[(x+3)(5x+1)\]

Answer 3

set each factor = 0 and solve. get
\[x=-3\] or
\[x=-\frac{1}{5}\]