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OpenStudy (anonymous):
consider the following quadratic equation: 5x^2+16x+9=6 using the standard form ax^2+bx+c=0 of the quadratic equation above, factor the left hand side equation into two linear factors
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OpenStudy (anonymous):
\[5x^2+16x+3=0\] is a start
OpenStudy (anonymous):
\[(x+3)(5x+1)\]
OpenStudy (anonymous):
set each factor = 0 and solve. get \[x=-3\] or \[x=-\frac{1}{5}\]
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