Question

no.7 and no.8 my last question to my test h.w
given that f(x) = 2x^2 - 3x + 4 and g (x) = 3x^2 + 4x - 5, find:
1. (f+g)(-2)
2. (f-g)(-3)
3. (f . g) (2/3)
4. (f/g) (- 4/5)
5. (f o g) (3)
6. (gof)(-4)
7.(f o f) ( 3/2)
8. ( g o g) (-1/2)
pls answer 7 and 8 i want to sleep now =)

Answer 1

7. ( fof)(x)=f(f(x))=f(2x^2 - 3x + 4)=2(2x^2 - 3x + 4)^2-3(2x^2 - 3x + 4)+4
take x=3/2 n simplify

Answer 2

8. ( g o g) (-1/2)

g(g(x)) at x = -1/2

g(-1/2) = 3(-1/2)^2 + 4(-1/2) - 5
= 3(1/4) - 4/2 - 5
= 3/4 - 4/2 - 10/2
= 3/4 - 8/4 - 20/4
= 3/4 - 28/20
= -25/20

g(-25/20) now has to be solved to get the answer

Answer 3

use a calculator if you understand the concept; otherwise, do it out by hand :)

Answer 4

thank you sir