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4x^3/3 times (9/x)^3
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4x^3/3 * 9/x^3 4/3 * 9 4*3 = 12 <=======
the ^3 goes to the 9 and the x
\[\frac{4x^3}{3}*(\frac{9}{x})^3\]?
yes!
That is: 4*729/3=972
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ah, in that case it is a bit bigger :P 972
\[\frac{(4x^3)*9^3}{3*x^3}\]
\[\frac{2.916x^2}{3x^3}=972
thanks everyone!
\[\frac{2.916x^3}{3x^3}= 972\]
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