decker has one allot containing 27% copper and another containing 60% copper. How many pounds of each must he use to make 49 pounds of a third alloy containing 39% copper? Round to the nearest hundredth

Question

decker has one allot containing 27% copper and another containing 60% copper.  How many pounds of each must he use to make 49 pounds of a third alloy containing 39% copper?  Round to the nearest hundredth

anonymous · Answer

mansonandmax you here for this?  because it is not hard

anonymous · Answer

well it might not be for you but it is for me...  if they are that easy for you then IGNORE my posts!!!!!

anonymous · Answer

that is not the point.  i tried replying to the last one but did not get a response. just wanted to make sure you were here

anonymous · Answer

so we go slow.  decker is going to end up with 49 pounds of an alloy that is 39% copper.  how much actual copper is there?

anonymous · Answer

that is, is it clear what 39% of 49 is?

anonymous · Answer

let x for  27% 
let y for  60% 
x+y= 49

    y = 49-x
0.27x+0.6y=49*0.39
Substitution  y = 49-x
0.27x+0.6( 49-x)=49*0.39
0.27x+29.4-0.6x=19.11
               - 0.33x=19.11 - 29.4   
                       x= -10.29/-0.33
                        x= 33
Substitution  x = 33
     33+y= 49
            y= 49-33
            y=16
27% need 33 pounds
60% need 16 pounds
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