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OpenStudy (anonymous):
factor each exprssion by factoring out the common binomial: 6y^3(x-2)+7(x-2)
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OpenStudy (anonymous):
I have posted the step and explanation on: http://www.oojih.com/show/algebra/polynomials/ scroll down to comment section to see your question
OpenStudy (anonymous):
hmm the common here 6y^3(x-2)+7(x-2) is (x-2) therefore, =(6y^3+7)(x-2)
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