Question

Find the sum of the first 32 terms of the following sequence:

-10, -2, 6 . . .

Answer 1

\[Sn = n/2[2a _{1}+(n-1)d]\]

Answer 2

n = 32
d = 8
\[a _{1}= -10\]

Answer 3

\[=32/2[2(-10) + (32-1)8]\]

Answer 4

= 16[-20 + (31)8]

Answer 5

= 16 (-20 + 248)
= 16 (228)
= 3648