Question

(12 over a-b+z) - (24 over b-a-z) pls help me

Answer 1

what are you trying to do?

Answer 2

subtraction of rational expressions

Answer 3

12/(a-b+z) - 24/(b-a-z)

First multiply the first part by (b-a-z)/(b-a-z)
And the second part by (a-b+z)/(a-b+z) (Finding common denominators)

[12(b-a-z)/(b-a-z)(a-b+z)] - [24(a-b+z)/(a-b+z)(b-a-z)]

Now subtract

12(b-a-z) - 24(a-b+z)
---------------------
(b-a-z)(a-b+z)

12b -12a-12z - 24a + 24b - 24z Multiply the top...
----------------------------------------
(b-a-z)(a-b+z)


36b - 36a - 36z ...and simplify
------------------
(b-a-z)(a-b+z)


36(b-a-z) Pull out 36
---------------
(b-a-z)(a-b+z)


36
----- and cancel out
a-b+z

Answer 4

tnx. i got the reverse answer for this question hehe