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(1/3)^x=1/9 solve the equation for x. Round to the nearest two decimal places
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x=2
\[3^{-x} = 3^{-2}\] -x = -2 x = 2
ok thanks to both of you can you tell me if im correct when I say e^x=4 and x=1.39
take logarithm to the base e, and check your log book for Log 4 base e..
(1/3)^x = (1/9) Solution: => ln(1/3)^x = ln(1/9) {multiply both sides by natural log ln} => x*ln(1/3) = ln(1/9) {exponent rule for log/ln} => x = ln(1/9) / ln(1/3) => x = 2
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Pepsa, you are correct.
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