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Find the solution set. Separate the two calues with a comma: x^2+6x+8=0
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x^2 + (m+n)x + (mn) = 0 is the setup we need to find m and n
m and n are factors of 8; 1(8); 2(4) m+n are the two factors of 8 that add up to 6 1+8 = 9 2+4 = 6
use the quadratic formula: \[x = -3 \pm \sqrt{9-8} = -3 \pm 1 =(-4,-2)\]
(x+m)(x+n) = 0 (x+4)(x+2) = 0 when x+4 = 0 or x+2 = 0
Thanks XaLeX
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