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write the first four terms of the sequence for n=1,2,3, and 4. f(n)=2n^2
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f(1) = 2*1² = 2 f(2) = 2*2² = 2*4 = 8 f(3) = 2*3² = 2*9 = 18 f(4) = 2*4² = 2*16 = 32
2, 8, 18, 32
thank u sooo... much
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