Question

if m(to the 6th power) = 3/y and m (to the 5th power) = y(squared) / 6 then which of the following expresses m in terms of y?
A) 18/y(cubed)
B) y(cubed)/18
C) y/2
D) 2/y
E) 18- y(squared)/6y

Answer 1

In this problem u can take m^5 common out of m^6 and then replace the value of m^5 ..
then obtain the value of m in y terms

Answer 2

A)
divide first equation by second