A young equestrian loved to ride her horse all day long, dreaming of the day she would ride in the Kentucky Derby. One day in early April, she left home at 10:00 am and rode her stallion at a nice, steady 10 miles per hour away from her house. At noon a call came in from the Derby saying she was in! Her father immediately jumped on his scooter to try and track her down and tell her the good news.

Riding at a breezy 15 miles per hour, after how many hours on the scooter will her father catch up to her?

Question

A young equestrian loved to ride her horse all day long, dreaming of the day she would ride in the Kentucky Derby. One day in early April, she left home at 10:00 am and rode her stallion at a nice, steady 10 miles per hour away from her house. At noon a call came in from the Derby saying she was in! Her father immediately jumped on his scooter to try and track her down and tell her the good news.

Riding at a breezy 15 miles per hour, after how many hours on the scooter will her father catch up to her?

anonymous · Answer

15x=10(t+2)
We already know that they are both traveling the same distance when her father is to've catched up. So we would need to write the distance equation  distance= speed x time.t is the time her father is to've met up with her and t+2 is time she was on the road.
SOLVE

anonymous · Answer

x is supposed to be t