Question

can sum1 please help me with this. Rectangle WXBY and square DWYF are joined at segment WY such that AD = 24 and BY = 40. Which is DX?


Answer 64.78
60.78
56
54

Answer 1

where's ad?

Answer 2

First you need to find the length of DW. You are told the klength of AD is 24 and that the angle DAW is 60 degrees. Therefore you have a right angled triagle and can use trig. \[\sin 60 = \frac{DW}{24}\] or rearranged, \[DW=24\sin 60\]. Now BY =40, and as you have a rectangle, then WX also equals 40. So the length \[DX=DW+WX\]