Find the slant asymptote of f(x)=18x^2/9x-8?

Question

amistre64 · Answer

divide it all by x methinks  or the sensible option would be to divide it thru

anonymous · Answer

I know you divide 18x^2 by 9x-8 and I get 2x+1 with a remainder of 7x-8 and it just doesn't look right nor does the computer think it is right.

amistre64 · Answer

2x +16/9
         ----------
9x-8/18x^2
        -18x^2+16x
        ------------
                      16x
                    -16x - (something else that goes away)

amistre64 · Answer

http://www.wolframalpha.com/input/?i=%2818x^2%29%2F%289x-8%29

anonymous · Answer

ah I see. By doing this all of my x's are out of the bottom, which leaves me with a semi clean remainder. Thank you for helping me figure out where I was going wrong!

amistre64 · Answer

$$\color{purple}{\text{youre welcome :)}}$$