Question

Find the slant asymptote of f(x)=18x^2/9x-8?

Answer 1

divide it all by x methinks or the sensible option would be to divide it thru

Answer 2

I know you divide 18x^2 by 9x-8 and I get 2x+1 with a remainder of 7x-8 and it just doesn't look right nor does the computer think it is right.

Answer 3

2x +16/9
----------
9x-8/18x^2
-18x^2+16x
------------
16x
-16x - (something else that goes away)

Answer 4

http://www.wolframalpha.com/input/?i=%2818x^2%29%2F%289x-8%29

Answer 5

ah I see. By doing this all of my x's are out of the bottom, which leaves me with a semi clean remainder. Thank you for helping me figure out where I was going wrong!

Answer 6

\[\color{purple}{\text{youre welcome :)}}\]