BE is tangent at C. AC and CD are chords such that the measure of arc DC=72° and the measure of arc AD=88°. Find m∠ECD, ∠ECA and m∠ACD.

Question

anonymous · Answer

attachment

anonymous · Answer

helppp

anonymous · Answer

don't u have radius for the circle

anonymous · Answer

uhmmmm

amistre64 · Answer

ECD is half of arcCD; ECA is half of arcACD; and ACD is half of arcAC

anonymous · Answer

A. 72°; 160°; 88°		B. 36°; 44°; 88°
	C. 36°; 80°; 44°

amistre64 · Answer

36 is the first one

anonymous · Answer

Well, those two chords form what is called an inscribed angle, and an inscribed angle always has half of the angle of the arc it subtends, so angle acd is 44.

amistre64 · Answer

360 - 88 = 272, 272=72 = 200 for arcAC but that doesnt seem to play nice

they might mean ACD is 88 degrees tho, hard to tell

amistre64 · Answer

im gonna guess its B ..... but i got no real proof for that

amistre64 · Answer

ack .... wasnt seeing the picture good ..

anonymous · Answer

You're sure that dce is 36? Because ACD is definitely 44. So that would make ECA just equal to DCE + ACD = 36 + 44 = 80

amistre64 · Answer

im gonna say C :)

anonymous · Answer

Yeah. It's c.

amistre64 · Answer

i was dyslexing the letters ...

anonymous · Answer

For one thing, you can see that the first and last angle should sum to form the second angle. That disqualifies B as a choice.

anonymous · Answer

i'm with c