Question

Find the vertex of this parabola:
y=5x^2+10x-3

Answer 1

Magic vertex formula...
x=-b/2a

Then plug back into the equation to get y.

Answer 2

\[y=5(x^2+2x)-3\]
\[y=5(x+1)^2-3-(5*1)\]\[y=5(x+1)^2-8\]
x=-1
y=-8