Question

You roll a blue die and a yellow die. What is

P(the sum of the dice is at least 6 | the blue die shows a 3)?

Write fractions using the slash ( / ) key. Reduce fractions to their lowest terms.

Answer 1

is this conditional probability?

Answer 2

blue die shows a 3 is the condition right?

Answer 3

i think so

Answer 4

lol you think so?!?.. ok this is easy to solve, your sample space reduces to only 6 cases.. in which the blue die is 3 and the yellow die from 1 to 6.. so pick out the ones which match your condition.. and tell me if you get the answer

Answer 5

would it b 3?

Answer 6

probability is always less than one or at the max equal to one

Answer 7

well the blue die is 3 and the only number that can b added to 3 to get six is 3

Answer 8

The question is atleast six, so the sum can be six and more than that.. so how many out of a total of 6 cases match that case??

Answer 9

3+3=6
3+4=7
3+5=8
is that wat u mean?

Answer 10

P(the sum of the dice is at least 6 | the blue die shows a 3)
is read as "the probability that the sum of the dice is at least 6 GIVEN that the blue die shows a 3.

Answer 11

the cases are

(1,3) (2,3).. (6,3).. total 6 cases.. now tell how many from these match your question??

Answer 12

lets think:
Blue die will always be 3
the sum of the yellow die and the blue die we want to be at least 6 (means 6 0r more)
Yellow Die Blue Die
1 3 does not equal 6 or more
2 3 '''' '''
3 3 =6
4 3 >6
5 3 >6
6 3 >9
thats all the possible rows given that the blue die is 3
so there are 6 rolls in all there and only 4 are them have sum of at least 6
so the probability is 4/6=2/3

Answer 13

>9
6*

Answer 14

You roll a blue die and a yellow die. What is

P(at least 6 | the blue die shows a 3)?

P(AnB)/P(B)

blue
1 2 3 4 5 6
1 x
y 2 x
e 3 x
l 4 x
l 5 x
o 6 x
w

P(B) = 6/36


blue
1 2 3 4 5 6
1
y 2
e 3 x
l 4
l 5
o 6
w

P(AnB) = 1/36

1/36
----- = 1/6 if i did it right
6/36

Answer 15

ack ... at least .. got it

Answer 16

no amist.. 2/3 is the answer..!

Answer 17

Yeah. You saw your mistake. Good explanation otherwise though.

Answer 18

im getting to it :) just gotta wade thru my stupidity to get there :)

Answer 19

go to second table you need more x's

Answer 20

Ahahaha I totally relate.

Answer 21

amistre how am i going to get 230 medals?

Answer 22

blue
1 2 3 4 5 6
1 x x x x x
y 2 x x x x
e 3 x x x
l 4 x x
l 5 x
o 6
w

P(A) = 15/36

P(AnB) = P(A) * P(B) = 15/36 * 6/36 = 90/1296

90/1296
-------- = 90/1296 = 5/72 hmmm
216/1296

Answer 23

you already have 770 medals :)

Answer 24

90/216 lol :) let me try that again

Answer 25

i get 5/12 but i dunno ..

Answer 26

lol

Answer 27

hey amistre look at my chart