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a+1 over 6 = 2/a what is a
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\[(a+1)/6=2/a\] multiply both sides by 6a what would you get?
6a^2+1 = 12a^2
a(a+1)=12 a^2 +a-12=0 use quadratic formula to find a what did you get for a?
3
or you can re-write it as: (a+4)(a-3)=0 (i used quadratic formula to find roots... honestly...) so, the answer would be: a=3 and a=-4
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