Find the vertex, the line of symmetry the maximum or minimum value of the quadratic function, and graph the function.

f(x)=-2x^2+2x+9

Question

Find the vertex, the line of symmetry the maximum or minimum value of the quadratic function, and graph the function.

f(x)=-2x^2+2x+9

anonymous · Answer

I got the answer (1/2 , 19/2) and I need to simplify so I put (1/2, 8) and that was not it

anonymous · Answer

This is Algebra...I believe

anonymous · Answer

this involves differentiation.. ! to find maximas and minimas

anonymous · Answer

yes, I am taking math 117 at phoenix

anonymous · Answer

i bet jimmy is giving a huge lecture..so just wait for his reply :D

anonymous · Answer

vertex is -2 / -4 = 1/2,y
y = -2*1/4 + 1 + 9
= 19/2
vertex = (1/2 , 19/2) or (0.5,9.5)
line of symmetry is x = 1/2

term in x^2 is negative so function has a maximum

this is at (1/2, 19/2)  or (0.5,9.5)

anonymous · Answer

To get maxima or minima differentiatie so you ll get$$-4x+2=0$$ this gives x = (1/2).. substitute this value and you ll get your maxima or minima

anonymous · Answer

maximum value of the function is 9.5