Question

A particle moves according to a law of motion s = f(t) = t^3 - 9t^2 + 15t, t >= 0, where t is measured in seconds and s in feet.

a)Find the total distance traveled during the first 7 seconds

Answer 1

that is wrong...

Answer 2

F(t)= position
F(t)= Velocity=\[(3 t^2 - 18 t + 15)^2\]
Speed=\[\sqrt{\left(3 t^2-18 t+15\right)^2}\]
Distance=\[\int_0^7 \sqrt{\left(3 t^2-18 t+15\right)^2} \, dt\]=71

Answer 3

WOW it was right....Thank you

Answer 4

I knew it was not gonna be easy as plugging a number in

Answer 5

but why will you square something under a square root

Answer 6

i never seen this before

Answer 7

to take the absolute value