0.3 x-0.2y=4 0.2x+0.3y=5/23 solve by using the elimination method

Question

anonymous · Answer

multiply the first equation with 3 and the second equation with 2 and add them up.
you will eliminate y

anonymous · Answer

IM STILL CONFUSED

anonymous · Answer

did you try doing what I said?

anonymous · Answer

YES

anonymous · Answer

what did you get? post it here

anonymous · Answer

I DONT GET IT SORRY

anonymous · Answer

well, you just said you tried doing what I said. I am asking you to post what you got so that we can see where you are getting stuck.

anonymous · Answer

oh. sorry, can't do your problems for you. ask someone else.

anonymous · Answer

0,3x-0,2y =4 ....(1)
0,2x+0,3y=5/23...(2)

first multiple (1) with 20
so, being 6x-4y=80.... (1)'
second multiple (2) with 30
so, 6x+3y=150/23....(2)'

third eliminate (1)' with (2)'
being -7y =80-150/23
          -7y = 73,48
             y = - 10,49

and then substitute y to (1)'
so, 6x-4(-10,49) =80
     6x+41,96=80
                6x = 80-41,96
                6x = 38,04
                  x =6,34

anonymous · Answer

SO HOW WOULD THE ANSWER APPEAR ( 6,34)