Question

Width of rectangle is 8 more the length. The perimeter is 56. Help me solve with steps?

Find the dimentions
Find the area?

Answer 1

lets say the length is L
then the width is L+8
the perimeter is 2(length+width)
so,
56 = 2(L+L+8)
solve for L. that is the length. width is 8 more than length.
area is length times width

Answer 2

Alright, let's let the width be w and the length be l.
We know that
w = l + 8

and we know the the perimeter is
2w + 2l = 56

Then we can substitute the first equation into the second to get:
2(l + 8) + 2l = 56
2l + 16 + 2l = 56
4l = 40
l = 10.

Then we can use the first equation again to get w = 10 + 8 = 18.

So the dimensions are 10x18. The area is just the length times the width, so 18 * 18 or 180.

Answer 3

*10*18 or 180.

Answer 4

W=8+L
2L+2W=56
-----------------
2L+2(8+L)=56
4L+16=56
4L=40
L=10

so
W=8+10=18

A=LW=18(10)=180

Answer 5

the area would be 180 good thanks