Question

log2(3/8)-log2(3), probably easy but logs are not my thing.. help?

Answer 1

= log2(3)-log2(8)-log2(3)
= -log2(8)

Answer 2

is it log(base2)(3/8)-log(base2)(3)?

Answer 3

yeah, definitively

Answer 4

= log2(3)-log2(8)-log2(3)
= -log2(2^3)
=-3 Sorry I missed this last step.

Answer 5

thank you so much!
i am starting to like 'em logs now

Answer 6

Thats good. Dont forget to click the "Good Answer" buttom

Answer 7

any time :)

Answer 8

thanks

Answer 9

log(base2)(3/8)-log(base2)(3)
=log(base2)(3/8*3)
=log(base2)(1/8)
=log(base2)(1)-log(base2)(8)
=0-log(base2)(8)
=-log(base2)(8) ans...

Answer 10

yeah, but -log2(8) = -3
this is a longer way