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we have e^ln(x) = ? for each positive number x, and ln(e^x) =? for all real numbers x.
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first one =x second one =x
Both are just x. You have inverse functions. So you have: \[f(x) \] and \[f^{-1}(x)\] In the first case you have: \[f(f^{-1}(x))\] And in the second you have: \[f^{-1}(f(x))=x\]
take e^lnx = y.. and take ln on both sides .. then take antilog ..
Think about x^2 and sqrt(x). If you have (sqrt(x))^2 or sqrt(x^2). Both are x.
ans = X in each case
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