Triangles ABC and LMN are given such that

AB = 24, BC = 20, and AC = 40
LM = 6, MN = 5, and LN = (3a + 1)
To be similar, which should be the value of a?
6
5
4
3

Question

Triangles ABC and LMN are given such that

AB = 24, BC = 20, and AC = 40
LM = 6, MN = 5, and LN = (3a + 1)
To be similar, which should be the value of a?
  6 
   5 
   4 
   3

anonymous · Answer

40/(3a+1)=4
4 is the similarity ratio which can be equal to 24/6 or 20/5
40/(3a+1)=4
40=12a+4
36=12a
a=36/12
a=3

anonymous · Answer

thank you :)

anonymous · Answer

but i dont think they framed it correctly coz 20/10=2 and the ratio was found to be 4 but thats my answer

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